Integrand size = 20, antiderivative size = 48 \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=-\frac {A \left (a+b x^2\right )^3}{8 a x^8}+\frac {(A b-4 a B) \left (a+b x^2\right )^3}{24 a^2 x^6} \]
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Time = 0.02 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {457, 79, 37} \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=\frac {\left (a+b x^2\right )^3 (A b-4 a B)}{24 a^2 x^6}-\frac {A \left (a+b x^2\right )^3}{8 a x^8} \]
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Rule 37
Rule 79
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {(a+b x)^2 (A+B x)}{x^5} \, dx,x,x^2\right ) \\ & = -\frac {A \left (a+b x^2\right )^3}{8 a x^8}+\frac {(-A b+4 a B) \text {Subst}\left (\int \frac {(a+b x)^2}{x^4} \, dx,x,x^2\right )}{8 a} \\ & = -\frac {A \left (a+b x^2\right )^3}{8 a x^8}+\frac {(A b-4 a B) \left (a+b x^2\right )^3}{24 a^2 x^6} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.15 \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=-\frac {6 b^2 x^4 \left (A+2 B x^2\right )+4 a b x^2 \left (2 A+3 B x^2\right )+a^2 \left (3 A+4 B x^2\right )}{24 x^8} \]
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Time = 2.49 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00
method | result | size |
default | \(-\frac {a \left (2 A b +B a \right )}{6 x^{6}}-\frac {a^{2} A}{8 x^{8}}-\frac {B \,b^{2}}{2 x^{2}}-\frac {b \left (A b +2 B a \right )}{4 x^{4}}\) | \(48\) |
norman | \(\frac {-\frac {b^{2} B \,x^{6}}{2}+\left (-\frac {1}{4} b^{2} A -\frac {1}{2} a b B \right ) x^{4}+\left (-\frac {1}{3} a b A -\frac {1}{6} a^{2} B \right ) x^{2}-\frac {a^{2} A}{8}}{x^{8}}\) | \(53\) |
risch | \(\frac {-\frac {b^{2} B \,x^{6}}{2}+\left (-\frac {1}{4} b^{2} A -\frac {1}{2} a b B \right ) x^{4}+\left (-\frac {1}{3} a b A -\frac {1}{6} a^{2} B \right ) x^{2}-\frac {a^{2} A}{8}}{x^{8}}\) | \(53\) |
gosper | \(-\frac {12 b^{2} B \,x^{6}+6 A \,b^{2} x^{4}+12 B a b \,x^{4}+8 a A b \,x^{2}+4 a^{2} B \,x^{2}+3 a^{2} A}{24 x^{8}}\) | \(56\) |
parallelrisch | \(-\frac {12 b^{2} B \,x^{6}+6 A \,b^{2} x^{4}+12 B a b \,x^{4}+8 a A b \,x^{2}+4 a^{2} B \,x^{2}+3 a^{2} A}{24 x^{8}}\) | \(56\) |
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Time = 0.28 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.10 \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=-\frac {12 \, B b^{2} x^{6} + 6 \, {\left (2 \, B a b + A b^{2}\right )} x^{4} + 3 \, A a^{2} + 4 \, {\left (B a^{2} + 2 \, A a b\right )} x^{2}}{24 \, x^{8}} \]
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Time = 0.83 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.21 \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=\frac {- 3 A a^{2} - 12 B b^{2} x^{6} + x^{4} \left (- 6 A b^{2} - 12 B a b\right ) + x^{2} \left (- 8 A a b - 4 B a^{2}\right )}{24 x^{8}} \]
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Time = 0.19 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.10 \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=-\frac {12 \, B b^{2} x^{6} + 6 \, {\left (2 \, B a b + A b^{2}\right )} x^{4} + 3 \, A a^{2} + 4 \, {\left (B a^{2} + 2 \, A a b\right )} x^{2}}{24 \, x^{8}} \]
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Time = 0.41 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.15 \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=-\frac {12 \, B b^{2} x^{6} + 12 \, B a b x^{4} + 6 \, A b^{2} x^{4} + 4 \, B a^{2} x^{2} + 8 \, A a b x^{2} + 3 \, A a^{2}}{24 \, x^{8}} \]
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Time = 0.04 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.10 \[ \int \frac {\left (a+b x^2\right )^2 \left (A+B x^2\right )}{x^9} \, dx=-\frac {x^2\,\left (\frac {B\,a^2}{6}+\frac {A\,b\,a}{3}\right )+x^4\,\left (\frac {A\,b^2}{4}+\frac {B\,a\,b}{2}\right )+\frac {A\,a^2}{8}+\frac {B\,b^2\,x^6}{2}}{x^8} \]
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